Optimal. Leaf size=71 \[ \frac{a^2 A x^{m+1}}{m+1}+\frac{a x^{m+4} (a B+2 A b)}{m+4}+\frac{b x^{m+7} (2 a B+A b)}{m+7}+\frac{b^2 B x^{m+10}}{m+10} \]
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Rubi [A] time = 0.0400606, antiderivative size = 71, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 1, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.05, Rules used = {448} \[ \frac{a^2 A x^{m+1}}{m+1}+\frac{a x^{m+4} (a B+2 A b)}{m+4}+\frac{b x^{m+7} (2 a B+A b)}{m+7}+\frac{b^2 B x^{m+10}}{m+10} \]
Antiderivative was successfully verified.
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Rule 448
Rubi steps
\begin{align*} \int x^m \left (a+b x^3\right )^2 \left (A+B x^3\right ) \, dx &=\int \left (a^2 A x^m+a (2 A b+a B) x^{3+m}+b (A b+2 a B) x^{6+m}+b^2 B x^{9+m}\right ) \, dx\\ &=\frac{a^2 A x^{1+m}}{1+m}+\frac{a (2 A b+a B) x^{4+m}}{4+m}+\frac{b (A b+2 a B) x^{7+m}}{7+m}+\frac{b^2 B x^{10+m}}{10+m}\\ \end{align*}
Mathematica [A] time = 0.0513311, size = 66, normalized size = 0.93 \[ x^{m+1} \left (\frac{a^2 A}{m+1}+\frac{b x^6 (2 a B+A b)}{m+7}+\frac{a x^3 (a B+2 A b)}{m+4}+\frac{b^2 B x^9}{m+10}\right ) \]
Antiderivative was successfully verified.
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Maple [B] time = 0.008, size = 262, normalized size = 3.7 \begin{align*}{\frac{{x}^{1+m} \left ( B{b}^{2}{m}^{3}{x}^{9}+12\,B{b}^{2}{m}^{2}{x}^{9}+39\,B{b}^{2}m{x}^{9}+A{b}^{2}{m}^{3}{x}^{6}+2\,Bab{m}^{3}{x}^{6}+28\,B{b}^{2}{x}^{9}+15\,A{b}^{2}{m}^{2}{x}^{6}+30\,Bab{m}^{2}{x}^{6}+54\,A{b}^{2}m{x}^{6}+108\,Babm{x}^{6}+2\,Aab{m}^{3}{x}^{3}+40\,A{b}^{2}{x}^{6}+B{a}^{2}{m}^{3}{x}^{3}+80\,B{x}^{6}ab+36\,Aab{m}^{2}{x}^{3}+18\,B{a}^{2}{m}^{2}{x}^{3}+174\,Aabm{x}^{3}+87\,B{a}^{2}m{x}^{3}+A{a}^{2}{m}^{3}+140\,aAb{x}^{3}+70\,B{x}^{3}{a}^{2}+21\,A{a}^{2}{m}^{2}+138\,A{a}^{2}m+280\,{a}^{2}A \right ) }{ \left ( 10+m \right ) \left ( 7+m \right ) \left ( 4+m \right ) \left ( 1+m \right ) }} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.56837, size = 497, normalized size = 7. \begin{align*} \frac{{\left ({\left (B b^{2} m^{3} + 12 \, B b^{2} m^{2} + 39 \, B b^{2} m + 28 \, B b^{2}\right )} x^{10} +{\left ({\left (2 \, B a b + A b^{2}\right )} m^{3} + 80 \, B a b + 40 \, A b^{2} + 15 \,{\left (2 \, B a b + A b^{2}\right )} m^{2} + 54 \,{\left (2 \, B a b + A b^{2}\right )} m\right )} x^{7} +{\left ({\left (B a^{2} + 2 \, A a b\right )} m^{3} + 70 \, B a^{2} + 140 \, A a b + 18 \,{\left (B a^{2} + 2 \, A a b\right )} m^{2} + 87 \,{\left (B a^{2} + 2 \, A a b\right )} m\right )} x^{4} +{\left (A a^{2} m^{3} + 21 \, A a^{2} m^{2} + 138 \, A a^{2} m + 280 \, A a^{2}\right )} x\right )} x^{m}}{m^{4} + 22 \, m^{3} + 159 \, m^{2} + 418 \, m + 280} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 3.78817, size = 1057, normalized size = 14.89 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.12885, size = 448, normalized size = 6.31 \begin{align*} \frac{B b^{2} m^{3} x^{10} x^{m} + 12 \, B b^{2} m^{2} x^{10} x^{m} + 39 \, B b^{2} m x^{10} x^{m} + 2 \, B a b m^{3} x^{7} x^{m} + A b^{2} m^{3} x^{7} x^{m} + 28 \, B b^{2} x^{10} x^{m} + 30 \, B a b m^{2} x^{7} x^{m} + 15 \, A b^{2} m^{2} x^{7} x^{m} + 108 \, B a b m x^{7} x^{m} + 54 \, A b^{2} m x^{7} x^{m} + B a^{2} m^{3} x^{4} x^{m} + 2 \, A a b m^{3} x^{4} x^{m} + 80 \, B a b x^{7} x^{m} + 40 \, A b^{2} x^{7} x^{m} + 18 \, B a^{2} m^{2} x^{4} x^{m} + 36 \, A a b m^{2} x^{4} x^{m} + 87 \, B a^{2} m x^{4} x^{m} + 174 \, A a b m x^{4} x^{m} + A a^{2} m^{3} x x^{m} + 70 \, B a^{2} x^{4} x^{m} + 140 \, A a b x^{4} x^{m} + 21 \, A a^{2} m^{2} x x^{m} + 138 \, A a^{2} m x x^{m} + 280 \, A a^{2} x x^{m}}{m^{4} + 22 \, m^{3} + 159 \, m^{2} + 418 \, m + 280} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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